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Mathematics 19 Online
OpenStudy (anonymous):

help me simplify please

OpenStudy (anonymous):

OpenStudy (anonymous):

@precal please help

OpenStudy (precal):

attach as jpeg. no one likes to open .docx files

OpenStudy (anonymous):

OpenStudy (anonymous):

@precal okay i put up a jpeg

OpenStudy (precal):

simplify your radicals, try to get the numbers under the radicals the same

OpenStudy (anonymous):

The trick is to look for factors under the radical of each term that are squares and bring them outside the radical. So for example \[\sqrt{128}=\sqrt{64\times2}=8\sqrt{2}\]Then you can just gather like terms.

OpenStudy (precal):

listen to Richie66

OpenStudy (anonymous):

is it \[-4\sqrt{114}\]

OpenStudy (anonymous):

Ha - sorry precal - great minds think alike!

OpenStudy (precal):

yes they do

OpenStudy (anonymous):

Just take it a term at a time. The first term simplifies to \[8\sqrt{2}\]as we saw earlier. For the second term we want to find square factors of 112, so you could just try dividing 112 by all the squares less than half of it until you find one that goes in exactly. The squares are 48,36,25,16,9 and 4. Once you have found one that goes just write 112 as the product of this factor and the result of dividing it. Here's what I get: \[2\sqrt{112}=2\sqrt{16\times7}\]Then move the 16 outside the radical to give: \[2\times4\sqrt{7}=8\sqrt{7}\]Why dont you try with the last two terms?

OpenStudy (anonymous):

okay i got it it was -6 sqrt 2 minus 4 sqrt7

OpenStudy (anonymous):

Yes that's what I got.

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