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Mathematics 8 Online
OpenStudy (anonymous):

2x+2y-3z=-4 3y-z=-4 4x-y+z=4, solve by any method, can someone help me step by step

OpenStudy (anonymous):

solve for one and plug it into the other keep doing that.

OpenStudy (anonymous):

x = 1/2, y = -1, z = 1

OpenStudy (anonymous):

what method do you know?

OpenStudy (anonymous):

well none, but i kinda get the substitution method

OpenStudy (anonymous):

the substitution method is one way but this being a 3x3 system, it might get messy. when you did 2x2 systems, do you remember elimination?

OpenStudy (anonymous):

not really, like i know the answer i just need to see the steps

OpenStudy (anonymous):

i can show the steps in elimination if you like...

OpenStudy (anonymous):

ok please

OpenStudy (anonymous):

ok... elimination means you will be eliminating a variable so you have less to work with... this is the way it works with a 3x3 system.. 3x3 system ---> eliminate variable --->2x2 system ---> eliminate variable ---> 1x1 system or 1 equation with 1 variable.

OpenStudy (anonymous):

so we need to work our way down to 1 equation with 1 variable to solve the 3x3 system...

OpenStudy (anonymous):

notice the middle equation only has two variables so we can use that as one of our equations in our 2x2 system.

OpenStudy (anonymous):

still with me?

OpenStudy (anonymous):

yess

OpenStudy (anonymous):

ok so can we work together on the problem that i need help with

OpenStudy (anonymous):

that middle equation has the variables y and z... so if we can "combine" the first and last equations by eliminating x, we'll end up with 1 equation with the variables y and z...

OpenStudy (anonymous):

notice in A, i'm only working with the first and last equations. i'm gonna eliminate the "x" variable by multiplying the first equation by 2, then subtract the third equation... |dw:1340224360978:dw|

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