Question

Factor completely 64x2– 49

Answer 1

Difference of squares:

\( \color{Black}{\Rightarrow (8x)^2 - 7^2}\)

a^2 - b^2 = (a + b)(a - b)

can you do it now?

Answer 2

Use\[a^2b^2=(ab)^2\]

Answer 3

Do you mean \[64x ^{2}-49\]

Answer 4

yes

Answer 5

\[64=8^{2}\]
Replace 64 with that, and you get:
\[8^{2}x^{2}-7^{2}\]
\[8^{2}x^{2}\] is the same as 8*8*x*x, or 8*x*8*x. That can also be written as (8*x)(8*x).
That can be written as \[(8*x)^{2}\]

From there follow what @ParthKohli posted.

Answer 6

thanks :)

Answer 7

(7x – 8)(7x + 8)

(7x – 8)(7x – 8)

(8x – 7)(8x – 7)

(8x – 7)(8x + 7)

These are the choices i have

Answer 8

\[(8x)^{2}−7^{2}\]
\[a^{2}−b^{2}\]

so:
\[(8x)^{2}=a^{2}\]

\[7^{2}=b^{2}\]
Known theorem:
\[a^{2}−b^{2}=(a+b)(a−b)\]