Question

so I need someone to help me with balancing equations: I have done most of them I just want to see if they are correct. My books doesn't have answers.

Answer 1

I can check what you've done if you still want to?

Answer 2

yes please, they are quite a lot though..

Answer 3

I do have to leave in a bit but I'll try to do as many as possible :)

Answer 4

chemical equations for weak electrolytes undergoing dissociation:
HCN +H2O--->H3O+ + CN-?

Answer 5

The balancing is correct. I haven't worked with these types of reactions though so I won't know what the products would be!

Answer 6

lol me too oh well thank you, next one (:

Answer 7

Hahah alright :)

Answer 8

two-step dissociation of the acid H2SeO3
H2SeO3 + H2O ----> H3O + HSeO3-
HSe03- + H20 -----> H3O + SeO3-

Answer 9

All correct!

Answer 10

H2SO3-->H(+) + HSO3(-)
HSO3(-)-->H(+) + SO3(2-)

Answer 11

Oh, is that sulfur or selenium?

Answer 12

I have no clue

Answer 13

okay so I gave the last one the wrong charge..

Answer 14

sorry, i wrote equations with sulfur :)

Answer 15

net ionic equations: I had problems with these. i can never identify the spectator ions well..
NaBr + AgNO3---> AgBr + NaNO3: Ag + Br ---> AgBr

Answer 16

NaBr (s) + AgNO3 (aq) ---> AgBr (s) + NaNO3 (aq)

and the ionic equation is

NaBr (s) + Ag(+) (aq) ---> AgBr (s) + Na(+) (aq)

Answer 17

you are forgetting the NO3

Answer 18

The nitrate ion would be the spectator ion so it's cancelled out of the ionic equation

Answer 19

Do you understand what I have done?

Answer 20

but there are always two spectators..

Answer 21

sodium and nitrate never changed signs..so they are spectators right?

Answer 22

Oh hang on, it depends on whether or not NaBr is a solid or aqueous solution in this reaction... If it is aqueous then yes, sodium is also a spectator

Answer 23

its two aqueous solutions reacting to form a solid and an aqueous solution.

Answer 24

Oki doki, yep you're right. The sodium ion and nitrate ion are both spectators so the ionic equation would be...

Br(-) (aq) + Ag(+) (aq) ---> AgBr as you said but don't forget the - and + to show that they are ions!

Answer 25

o okay (:

Answer 26

so every time its two aqueous solutions then the products a solid and an aqueous solution, its always the aqueous solution product that is a spectator?

Answer 27

Sometimes two aqueous solutions don't produce a precipitate (a solid). You can check which ionic substances are soluble in water or not using a solubility table. Do you have one?

Answer 28

There is an easy way to find out ionic equations from molecular equations. Let me show you an example :P

Answer 29

Eg. The neutralisation reaction of hydrochloric acid and sodium hydroxide..

Molecular equation: HCl (aq) + NaOH (aq) ---> NaCl (aq) + H2O (l)

To find ionic equation: Split aqueous substances into ions then cancel out common ions.

H(+)(aq) + Cl(-)(aq) + Na(+)(aq) + OH(-)(aq) ---> Na(+)(aq) + Cl(-)(aq) + H2O (l)

In this case, the chloride ions and sodium ions are on both sides of the reaction so we can cancel them out. This leaves the ionic equation.

H(+)(aq) + OH(-)(aq) ---> H2O(l)

This is the way our teacher taught us :)

Answer 30

oh, i don't have a table for solubles but I have a part of my book which gives me a sort of list.. do you the table?

Answer 31

oh yes, I know the ionic splitting method but it tends to confuse me; but if that's the trick i'll always use it... are you going soon?

Answer 32

Oh okay, well it's always easier to know if the products are soluble or not :P That table which I posted is a leeeegeeeeend. It's on our school chemistry data sheet. And yeah I have to leave now :( Hope I helped somehow, good luck!

Answer 33

So if you look AgBr on the solubility table, it says insoluble so you would know that it is a solid

Answer 34

thank you! you did a lot! :)

Answer 35

No problem, see you later! :)

Answer 36

if anyone is willing to help please just post.. we werent done...

Answer 37

where were you stuck?

Answer 38

well, I did the equations already.. I just need someone to check if they are correct.

Answer 39

net ionic equations:
CoCO3 + 2HNO3 ---> Co(NO3)2 + CO2 + H2O
Co+ + 2NO3- ----> Co(NO3)2

Answer 40

that's ok, something else?

Answer 41

so sorry kryten, i have a lot but i need to go out to get a math book.. i'll post some more later :/ sorry

Answer 42

@Kryten
1. NaC2H3O2 + HNO3 ----> NaNO3 + HC2H3O2
C2H3O2- + H+ ----> HC2H3O2
2. Pb(NO3)2 + (NH4)2SO4 ----> PbSO4 + 2NH4NO3
2NO3- + 2NH4+ ----> 2NH4NO3
3. H2S + Cu(NO3)2 ----> 2HNO3 + CuS
S+ + Cu- ----> CuS
4. NaOH + NH4Cl ---> NH3 + H20 + NaCl
OH- + NH4+ ---> NH3 + H20