Permutation question: please find it in the picture below:
b) 8P20 = 6720
Please explain... :(
shouldnt it be \[\frac{8!}{(8-5)!}\]
you have 8 distinct alphabets..you'll form 5 letter words
therefore you get \[\frac{8!}{(8-5)!} = \frac{8!}{3!}\]
8P20 = 8!/(8-5)!
^not 20, 5
that's also equal to \[\frac{8 \times 5 \times 4 \times \cancel{3!}}{\cancel{3!}} = 8 \times 7 \times 6 \times 5 \times 4 = 6720\]
that'show it was got
If i have the 8 letters {a,b,c,d,e,f,g,h} and pick 5 of them, I could start with any of them, so I have 8 ways of doing this. Next, I have 7 letters left, so I have 7 ways of doing this. Then I have 6, Then 5. Then 4. End So 8*7*6*5*4 = 6720 let n = total number of letters let r = total chosen Formula to get answer is nPr (its on your calculator) But expanded, its simply: n! ______ (n-r)!
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