Question

find the product (8x-3y)2

Answer 1

Is the 2 an exponent, or being multiplied to (8x - 3y) ?

Answer 2

\[(a-b)^2 = a^2 + b^2 - 2ab\]

Answer 3

Put,

a = 8x
b = 3y

Answer 4

exponent 2

Answer 5

The square of a binomial is the sum of:
-the square of the first term
-the square of the second term
-twice the product of the first and second term

@vishweshshrimali5
has already put it in figures for you :)

Answer 6

need a complete solution

Answer 7

\[(8x-3y)^2 = 64 x^2 + 9y^2 - 2(8x)(3y) = 64x^2 + 9y^2 - 48xy\]

Answer 8

where did you get that # 2 ? that is (8x-3y)2 means exponent

Answer 9

-2 rather

Answer 10

First term is 8x, right?
Second term is -3y.

First term squared is 64x^2
Second term squared is 9y^2
The product of the first and second term is -24xy, and you multiply this by 2, giving you
-48xy

And add these up, you have your product :)

Answer 11

ok thank you ... hoa about this .can you help me again

Answer 12

(a+2/3)2 the exponent is 2

Answer 13

ok, your first term is a
your second term is 2/3

what's the square of your first term?

Answer 14

i dont knew that is only the given its my neighbor assignment and she needs a help thats why i cant explain that bcoz thats not mine .. but i wanna help her

Answer 15

hello

Answer 16

help me this complete solution i need ..find the product again ,(a+1/2) (a-1/2)

Answer 17

In general, you can always use what is called the FOIL method for getting the product of two binomials.

For instance, we have something of the form
(a + b)(c + d) :: FOIL stands for
F: First terms --> the first terms of the binomials, multiply them to get
ac
O: Outer terms --> the first term of the first binomial and the second term of the second, multiply them to get
ad
I: Inner terms --> the second term of the first binomial and the first term of the second,
multiply them to get
bc
L: Last terms --> the last (second) terms of the binomials, multiply them to get
bd

and just add them up :)
ac + ad + bc + bd