Question

PLEASE HELP

2x^2+4=-5-2x^2

or ( the 5 is a positive)

2x^2+4=5-2x^2

solve using the quadratic formula

Now I did this probably 5 times over and havnt gotten the right answer will show my work below.

Answer 1

first get everything on the same side

Answer 2

\[-4\pm \sqrt{4^{2}-4(4)(-5)} all \div by 2(4)\]

Answer 3

4x^2 + 0x + 9 = 0 is your new equation now a=4 , b=0, c= 9

Answer 4

\[or -4\pm \sqrt{4^{2}-4(4)(5)} all \div by 2(4)\]

Answer 5

what type the quadratic formula first using letters and you will know what your mistake is

Answer 6

OHHHH there is no x i am so sorry i overlooked that simple part

Answer 7

sorry I meant to say type** not what type

Answer 8

haha no reason to be sorry so do you want to show what the new formula looks like?

Answer 9

yes

\[-0\pm \sqrt{0^{2}-4(4)(9)} all diveded by 2(4) \]

Answer 10

let me do it quickly and see if i get an answer because now I think i can do it

Answer 11

yes that should work you know imaginary numbers right?

Answer 12

no what are those and I cant do this because the square root has a -144

what is wrong with that ?

Answer 13

oh wait why does it say or the 5 is a positive at the beginning of your question?

Answer 14

because the question where online and I looked really close and it looked like a -5, but when i did it my way that didn't work so I tried positive and got a closer answer

but if -5 works then it is that

Answer 15

If the five is a positive the c = -1 and you will have a real answer and if the 5 is a - then it is -9 and your answer will be i*sqrt(144) the i stands for sqrt of -1

Answer 16

well it was multiple choice the choices are

a) \[1+\sqrt{6} \div4 and 1-\sqrt{6}\]

Answer 17

b) \[-1+\sqrt{6} and -1-\sqrt{6}\]

Answer 18

c) \[1+\sqrt{6} \div4 and 1-\sqrt{6}\div4\]

Answer 19

d) \[1+\sqrt{6} and 1-\sqrt{6}\]

Answer 20

and if i say divide its the line under the numbers with the 4 on the bottom

Answer 21

sorry I shouldn't have said you answer I mean the part under the sqrt root you answer would be
-i12/8 = + or - (-i3/2) or if 5 is positive okay wait if none of the answers have an i then the 5 be positive

Answer 22

oh my you are gona kill me

the numbers from the start are wrong i typed them wrong

they are

\[2x^{2}+4x=-5-2x ^{2} \]

Answer 23

okay if you equation is 2x^2+4=5-2x^2
then you get
4x^2 - 1 = 0 and that mean a = 4, b = 0 and c = -1
\[(-0 \pm \sqrt{0 - 4*4*-1})/(2*4)\] so you should have
\[(\pm \sqrt{16})/(8)\]

Answer 24

lol it's cool just one second we will figure this out

Answer 25

its really driving me insane if you could see my notes i tried it every single way and it doesn't give me any of the answers

Answer 26

so if the 5 is actually a positive the end answer would be

\[-4 \pm \sqrt{16x6} / 8 \]

\[-4\pm 4\sqrt{6} / 8\]

Answer 27

and if the 5 is a - then

\[-4 \pm \sqrt{64} / 8 \]

and we didnt learn that there can be a negative in the square root so this is simply not an answer

Answer 28

and if we wanted to make things more fun the +5

could also be

\[-2 \pm 2 \sqrt{6} /4 \]

and this is so very close to the answers but now if you go on you get

\[0\sqrt{6} / 4 and -\sqrt{6}\]

Answer 29

2x^2+4x=5−2x^2
okay lets just assume the 5 starts off positive
4x^2 + 4x + 5 = 0
a = 4, b = 4, c=-5

\[ (−4\pm√(16 - 4*4*-5) )/(2∗4)\]
\[ (−4\pm√96 )/(8)\]
and I just checked on wolfram with the equation you gave me and it appears to be right and when it is simplified it looks more like one of the choices. (1/2)(-1-sqrt(6))

Answer 30

how did u get one of the answers since

\[-4 + 4 \sqrt{6} /8 \]

\[-1 + 1 \sqrt{6} \]

\[0 \sqrt{6} / 4\]

Answer 31

or do you multiply the numbers from the front of the square root ?

Answer 32

Do you know how to simplify to get to that answer? (−4±√96)/(8) is the same as (−4±√(6*16))/(8) and we can rewrite that as (−4±4√6)/(8) then factor out the four on top to get 4(−1±√6)/(8) and then then 4/8 becomes 1/2 so you have (−1±√6)/2

Answer 33

thank you so much I understand now so sorry for talking your time But thank you oh so very much

Answer 34

It's cool remember to read the question very carefully I always read stuff to fast and it messes me up too.