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Mathematics 7 Online
OpenStudy (anonymous):

Graphing inequalities help? Image included

OpenStudy (anonymous):

OpenStudy (fwizbang):

Are you trying to answer for the green region or the yellow?

OpenStudy (anonymous):

idk whatever the question asks i guess

OpenStudy (fwizbang):

The question you sent doesn't say. Let's assume its the green. Start by finding the equation for the dotted line....

OpenStudy (anonymous):

it's both green and yellow because there's 2 equations. right?

OpenStudy (fwizbang):

Yes, one of the equations cuts the plane in half, and the other cuts it in half again

OpenStudy (anonymous):

huh?

OpenStudy (fwizbang):

The first equation(line) divides the graph into two part, the green-yellow part and the unshaded part. The second equation(line) divides the green part from the yellow part

OpenStudy (anonymous):

okay what does that have to do with finding the equation?

OpenStudy (fwizbang):

one of the equations you need is the equation of the line that separates the shaded part from the unshaded part. The other is the equation of the line that separates the green from the yellow.

OpenStudy (anonymous):

oh

OpenStudy (fwizbang):

So start by finding the equation for the dotted line that divides yellow from green

OpenStudy (anonymous):

yeaahh, I don't know how.. /:

OpenStudy (fwizbang):

OK. Can you find the y-intercept from the graph?

OpenStudy (fwizbang):

look for the point where the line goes thru the y-axis

OpenStudy (anonymous):

3?

OpenStudy (fwizbang):

you got it. Let's call that number b. Now can you find the slope of the line?

OpenStudy (anonymous):

idk what the slope is

OpenStudy (fwizbang):

Slope tells you how steep the line is and whether it slants up or down. To find it's value, we need to find two points on the line. We have one, x=0 y=3, that you just found. Now follow the line until it hits the x-axis, what number is there?

OpenStudy (anonymous):

Indeed, fwizbang is correct, the higher the slope's #, the steeper it is. A slope of 2 means for every 2 units change in height (y-axis coordinate here) you go side-to-side only one unit. A steeper slope like a high-sloped roof. A slope of 1/2 would mean for ever 1 unit change in height, you'd go 2 units side to side. A shallower slope like you might have on a road (26.565\(^o\ in fact I believe).

OpenStudy (anonymous):

\[26.565^o\]

OpenStudy (anonymous):

you guys are confusing me -_______-

OpenStudy (fwizbang):

Sorry. We were trying to find the equation of the dotted line in your picture, right? One way to do that is to find its y-intercept(3), and its slope.....

OpenStudy (anonymous):

okay, i got that, now how do we find the slope?

OpenStudy (anonymous):

why can't we just do the substitute thing like the last one

OpenStudy (fwizbang):

To find the slope, we're going to find two points on the line, and then divide the change in y(the "rise") by the change in x(the "run"). So we need to find the x and y values for a second point on the line. An easy one to use ids the pint where the line hits the x-axis(the "x-intercept").

OpenStudy (fwizbang):

In the last one, we had the equations and were trying to find the picture. Here we have the picture, and are trying to find the equations

OpenStudy (anonymous):

the one before that, where there was a picture also you said something about substituting

OpenStudy (fwizbang):

We can't substitute if we don't have an equation to substitute into.

OpenStudy (fwizbang):

We're almost there, can you find the pint were the line hits the x-axis?

OpenStudy (anonymous):

3

OpenStudy (fwizbang):

Good. Now we have two points, the first had x=0 and y=3, and now the second has x=3 and y=0. So we're going to find the slope by finding the rise, which is the change in the y's rise = (2nd y) - (first y) = 0 - 3 = -3 and dividing it by the run, which is the change in the x's, run = (2nd x) - (first x) = 3 - 0 =3 so that the slope = rise/run = -3/3 = -1. Still with me?

OpenStudy (anonymous):

no you lost me

OpenStudy (fwizbang):

Ok. do you have the coordinates of the two points?

OpenStudy (anonymous):

3 and -1?

OpenStudy (fwizbang):

not quite. Remember the first point was where the line went thru the y-axis, so it had x=0 and y=3.

OpenStudy (fwizbang):

the second point was where the line went thru the x-axis, so it had y=0 and x=3. (all these 3's can be a little confusing.)

OpenStudy (anonymous):

0 and 3 aren't in my answer choices.. so it's D?

OpenStudy (fwizbang):

patience, we still have a little more to do

OpenStudy (fwizbang):

We have two points on one of the lines, we need to find its equation

OpenStudy (anonymous):

:(((((((((((

OpenStudy (fwizbang):

I'm sorry, but we can get thru this if we keep at it.....Can you find the change in the y's?(the rise)

OpenStudy (anonymous):

if i knew how.

OpenStudy (fwizbang):

The first point,where the line went thru the y=-axis, had y=3. The second point, where the line went thru the x-axis, had y=0. Subtract the first y from the second

OpenStudy (anonymous):

-3

OpenStudy (fwizbang):

Great, that's the "rise". Now do the same thing for the x's. The first point had x=0, the second had x=3. So, the "run" is ?

OpenStudy (anonymous):

3

OpenStudy (fwizbang):

Perfect. Now to find the slope, take the rise and divide it by the run

OpenStudy (anonymous):

1

OpenStudy (fwizbang):

Almost, the rise was -3 and the run was 3....

OpenStudy (anonymous):

-1

OpenStudy (fwizbang):

There you go. So the slope of the line is -1. Since the slope is negative it tells us that as we move to the righth in the ppicture, the line goes down. The -1 says that for every step we go to the right, the line goes one step down......

OpenStudy (fwizbang):

Theres a rule that says we can find the equation of the line by y = (slope) times x + y-intercept or, if slope = m, y=mx +b

OpenStudy (fwizbang):

Remember the first thing you found was the y-intercept(3), So the equation for our line is ?

OpenStudy (anonymous):

3=mx+b?

OpenStudy (fwizbang):

not quite, we want to keep the y and the x, but substitute for the slope(m) and the y-intercept(b)....

OpenStudy (fwizbang):

rember that the y-intercept(b) was 3 and the slope(m) was -1

OpenStudy (anonymous):

y=-1x+3?

OpenStudy (fwizbang):

Perfect. So now we have the first equation we need (y=-x+3). Already we can rule out answer a, right?

OpenStudy (anonymous):

yeah

OpenStudy (fwizbang):

So now we need to find the equation of the line that separates the shaded and unshaded regions. Remember how this works: 1) We need to find two points on the line. 2)The first easy point to find is the point were the line goes thru the y-axis. It has x=0, and its y-value(which we read off the picture) is the y-intercept(b) that appears in the equation of the line. 3) The second easy point to find is where the line hits the x-axis. It has y=0 and its x-value we can get off the picture. 4) To find the slope(m) , we find the change in the y-value(the rise) and divide it by the change in the x-values(the run) 5) the equation for the line is y=m x +b. The importtant thing is to remember that you just need to do this one step at a time, not all at once, so start with 1 and work your way down. Wanna give it a try?

OpenStudy (anonymous):

that's SO much work, plus i have another harder question after this :/ is there an easier way?

OpenStudy (fwizbang):

Every time you do it, it'll be quicker and easier, until you won't even have to think about it anymore, Can you try step 2?

OpenStudy (anonymous):

i thought we already did those steps

OpenStudy (fwizbang):

We did, but now we need to do it for the second line so we can get the second equation we need.

OpenStudy (anonymous):

-.-

OpenStudy (fwizbang):

Hang in there, we're going to get this. Can you find the point were the second line hits the y-axis?

OpenStudy (anonymous):

it doesn't

OpenStudy (anonymous):

oh wait, -2

OpenStudy (fwizbang):

There you go. That tells us that the y-intercept(b) is -2. Now find the point where the line hits the x-axis.

OpenStudy (anonymous):

1

OpenStudy (fwizbang):

great. So we have the two points we need x=0, y=-2, and y=0, x=1. We're ready for step 4. What are the rise and the run?

OpenStudy (anonymous):

-3 and -3?

OpenStudy (fwizbang):

aThat was for the first line, we're working on the 2nd now. remember that rise =2nd y - first y run = 2nd x- first x

OpenStudy (anonymous):

This is pointless -.- I don't understand what i'm doing and I don't know how to do this and I have 3 other quizzes to do.. This is just hopeless !

OpenStudy (fwizbang):

I'm sorry your frustrated. We're trying to find the equations for the two lines that appear at the edges of the green region so we can pick out the answer. We already have one, so if we can find the equation for the other we'll be essentially done.

OpenStudy (anonymous):

ughhhhh. how do we do the rise & run

OpenStudy (fwizbang):

Here's a different thing to try. On the picure, start at the first point and count hoe many boxes you have to go sideways to get to the second one.

OpenStudy (anonymous):

no id rather do it the way we did it last time, if that's okay?

OpenStudy (fwizbang):

ok. then take the first x(0), and subtract it from the 2nd x(1) to get the run.

OpenStudy (anonymous):

1

OpenStudy (fwizbang):

thats the run. Now find the rise = 2nd y - first y

OpenStudy (anonymous):

what were they again?

OpenStudy (fwizbang):

the 2nd y was 0, because the point is on the x-axis. The first y was the y-intercept(b), which was -1

OpenStudy (fwizbang):

opps, -2

OpenStudy (anonymous):

so it's -2

OpenStudy (anonymous):

?

OpenStudy (fwizbang):

Sorry, I had to take care of something else for a bit. 0 -(-2) = 2. So the rise is 2 and the run is 1. The slope is the rise/run =?

OpenStudy (anonymous):

2

OpenStudy (fwizbang):

the equation for the line is y = m x +b, where m is the slope and b the t-intercept, so we get.....

OpenStudy (anonymous):

y=2x+b ( i don't know what goes in place of b )

OpenStudy (fwizbang):

b is the y intercept, which was -2 in this case, so y=2x-2.

OpenStudy (fwizbang):

Hopefully, the 2nd time was a little easier(humor me), but the good news is that the hard part is done. We have the two equations we need y = -x + 3 and y =2x-2 the code in these pictures is that when a line is dotted, then the points on the line aren't part of the solution, so the = sign in the equation gets replaced with either a < or a >. When the line is solid, the points on the line are part of the solution, so the = is replaced by a >= or a <=. So the answer we want either has y< -x+ 3 or y>-x+3 and y>= 2x -2 or y<= 2x-2. To figure out which, we just have to pick any point in the green regionof the picture, say y=0 x=4, and substitute it in like we did before.....

OpenStudy (anonymous):

substitute where?

OpenStudy (fwizbang):

into the inequalities. If the inequality is true after you substitute, then its one of the two we want

OpenStudy (anonymous):

-______-

OpenStudy (fwizbang):

so if y=0 and x=4, is y< -x +3 correct?

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