An hourglass consists of two sets of congruent composite figures on either end. Each composite figure is made up of a cone and a cylinder.
Each cone of the hourglass has a height of 12 millimeters. The total height of the sand within the top portion of the hourglass is 47 millimeters. The radius of both the cylinder and cone is 4 millimeters. Sand drips from the top of the hourglass to the bottom at a rate of 10π cubic millimeters per second. How many seconds will it take until all of the sand has dripped to the bottom of the hourglass?

Question

An hourglass consists of two sets of congruent composite figures on either end. Each composite figure is made up of a cone and a cylinder. 
Each cone of the hourglass has a height of 12 millimeters. The total height of the sand within the top portion of the hourglass is 47 millimeters. The radius of both the cylinder and cone is 4 millimeters. Sand drips from the top of the hourglass to the bottom at a rate of 10π cubic millimeters per second. How many seconds will it take until all of the sand has dripped to the bottom of the hourglass?

anonymous · Answer

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anonymous · Answer

@FoolForMath

anonymous · Answer

1º find the volume of the cone 12mm heigh and radius 4 and the volume of the cilinder with radius 4 and 47-12 =35 heigh
2º add this 2 volumes.
3º devide the result by 10Pi to get the answer

anonymous · Answer

How do I find the volume of the cone?

anonymous · Answer

formula for cone volume: $$Vlume cone = 1/3 \pi r ^{2} h$$
where h is height, and r radius

anonymous · Answer

So v=1/3pi4^235
v=568.4? @myko

anonymous · Answer

r ^2=16
h=12
so: volume cone=1/3*Pi*192=64Pi

anonymous · Answer

volume cylinder = Pi*r^2*h = Pi *16*35=Pi560
adding bouth : 64Pi+Pi560=624Pi
deviding by 10Pi:   624Pi/10Pi =62,4 s

anonymous · Answer

Oh, I get it! Thank you!

anonymous · Answer

yw