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OpenStudy (anonymous):
boy u gotta pay attention more
OpenStudy (anonymous):
Y Im Here LOL
terenzreignz (terenzreignz):
by f(x)^-1, do you mean the inverse function, or the reciprocal of the function?
OpenStudy (anonymous):
Inverse
terenzreignz (terenzreignz):
The domain of f^-1 is the range of f
can you take it from here?
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OpenStudy (anonymous):
the domain of the inverse function is the range of your original function i.e. domain \(f^{-1}\) is the range of \(f\)
finding the range of \(f(x)=\frac{3}{x-2}\) is not trivial, but it is all real numbers except 0
OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
reason being that a fraction is only zero if the numerator is, and your numerator here is 3, so it is never 0
you can also find the expression for \(f^{-1}\) and then see directly what the domain is
OpenStudy (anonymous):
Thanks Alot
OpenStudy (anonymous):
do you know how to find \(f^{-1}\) explicitly ?
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OpenStudy (anonymous):
Yea
OpenStudy (anonymous):
then once you do that you should get \(f^{-1}(x)=\frac{1}{x}+2\) and you can see directly that the domain is all real numbers except 0