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Mathematics 9 Online
OpenStudy (anonymous):

DOMAIN of f(x)^-1 if f(x) = 3/x - 2

OpenStudy (anonymous):

boy u gotta pay attention more

OpenStudy (anonymous):

Y Im Here LOL

terenzreignz (terenzreignz):

by f(x)^-1, do you mean the inverse function, or the reciprocal of the function?

OpenStudy (anonymous):

Inverse

terenzreignz (terenzreignz):

The domain of f^-1 is the range of f can you take it from here?

OpenStudy (anonymous):

the domain of the inverse function is the range of your original function i.e. domain \(f^{-1}\) is the range of \(f\) finding the range of \(f(x)=\frac{3}{x-2}\) is not trivial, but it is all real numbers except 0

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

reason being that a fraction is only zero if the numerator is, and your numerator here is 3, so it is never 0 you can also find the expression for \(f^{-1}\) and then see directly what the domain is

OpenStudy (anonymous):

Thanks Alot

OpenStudy (anonymous):

do you know how to find \(f^{-1}\) explicitly ?

OpenStudy (anonymous):

Yea

OpenStudy (anonymous):

then once you do that you should get \(f^{-1}(x)=\frac{1}{x}+2\) and you can see directly that the domain is all real numbers except 0

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