Can someone help me with right triangles? please.
If the hypotenuse of a 45º-45º-90º triangle is 54 inches long, what is the length of one of the legs? Leave your answer in radical form.
If a is the length of a leg in a 45-45-90 triangle, the length of the hypotenuse is always \[a \sqrt{2}\] Consequently, if b is the length of a leg, then the length of the hypotenuse is \[\frac{b}{\sqrt{2}} = \frac{b \sqrt{2}}{2}\] IN the case where 54 is the length of the hypotenuse, then a leg will measure: \[\frac{54}{\sqrt{2}} = \frac{54\sqrt{2}}{2} = 27\sqrt{2}\] That's it, hope it helped :)
that did thank you very much ! :)
i have another 1 if you don't mind ?
hang on, my first answer wasn't quite right, let me rephrase... If a is the length of a leg in a 45-45-90 triangle, the length of the hypotenuse is always a2√ Consequently, if b is the length of the hypotenuse, then the length of the leg is b2√=b2√2 IN the case where 54 is the length of the hypotenuse, then a leg will measure: 542√=542√2=272√
Ok, I'm ready for your next question :)
A sphere has a diameter of 4 meters. What is the approximate volume of the sphere?
The volume of a sphere is given by this formula \[V = \frac{4}{3}\pi r^{3}\] Where r is the radius of the sphere and the value of pi is approximately \[\pi = 3.1416\]
Can you do it from here?
what do i do after that ?
Well, basically, you need a value for r what's r? :)
4 i think ?
r, or radius, is half the diameter :D If 4 is the diameter, then what is the radius?
2
That's right, so just plug it into the formula for the volume of a sphere :D \[V = \frac{4}{3}\pi r^{3}\] And you'll get the volume :)
which is 33.49 i got it thanks so much !
No problem :D
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