Write the equation of the line that passes through (1,2) and with a slope of -1/3 in standard form
Start with y = mx+b
We're given a slope of -1/3, so m = -1/3
This means y = mx+b becomes y = -1/3x + b
We also know it passes through (1,2), so x = 1 and y = 2 Plug these new values in to get 2 = (-1/3)*(1) + b Now solve for b
Thank you!
you're welcome
let me know what you get
I really only needed the method for solving the problem, see I am helping my daughter with entry level algerbra and I wanted to pose an example problem. Thanks for your help!
alright, I'm glad I could help
Oh one more thing, for this problem, y-3=1(x+4):::::: Write the equation of the line that passes through (-4,3) and with the slope of 1 in slope intercept form.::::: is that correct?
that's point slope form, so you'll have to solve for y and simplify
Thanks.. hm when I re-work it, I got 3x-4y=1.. is that right?
no, not sure how you got that
use y = mx+b again, this time plug in m = 1, x = -4 and y = 3 to solve for b
Ohhhhhh. It's y=x+7, isn't it
yes it is, nice work
couldn't have done it without your help haha
lol glad to help
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