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Which action will shift the equilibrium of this reaction to the right? AB(g) + C(g) jl A(s) + BC(g) a. adding A b. removing C c. increasing the pressure d. increasing the volume of the reaction vessel
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please help
i would say A, more reactant=more product = position of equilibrium to the right
thanks alot!
Increasing the pressure would shift the equilibrium to the right. AB and C are both in a gaseous state and when the pressure is increased within the reaction vessel, the probability of the gases coming into contact (and reacting) increases.
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