I'm trying to the sum (of a series)
It would help if you posted the actual question.
Give me a second to write it
\[sum_{n=1}^{infty} 3/(5^n) + sum_{n=1}^{infty} 2/n\]
does it make sense?
3/4 + non convergent = non convergent http://www.wolframalpha.com/input/?i=Sum%283%2F5^n%2Cn%2C1%2Cinf%29 http://www.wolframalpha.com/input/?i=Sum%282%2Fn%2Cn%2C1%2Cinf%29
sum= a/(1-r) is the common ration for the 1st term (1/5) and (1/2) for the second term
I don't remember any of this, I think you're better off posting the question in chat. But that's what I got from wolfram alpha.
Thanks for wolfram, but I need to be able to do this manually too... Thanks though
It has something to do with r>1, but I'm not sure what.
Here is how far I got... |dw:1340220488073:dw| this makes sense... but why is the second sum non convergent?
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