What is true about the solutions of a quadratic equation when the radicand of the quadratic formula is a perfect square?
Answer

No real solutions

Two identical rational solutions

Two different rational solutions

Two irrational solutions

Question

What is true about the solutions of a quadratic equation when the radicand of the quadratic formula is a perfect square?
Answer
		
No real solutions
		
Two identical rational solutions
		
Two different rational solutions
		
Two irrational solutions

anonymous · Answer

Two different rational solutions

anonymous · Answer

Two identical rational solutions.

cwrw238 · Answer

isnt 2 identical myko?

anonymous · Answer

If 'identical' means +/-

tennistar · Answer

um I have two answers now

anonymous · Answer

$$x=-b \pm \sqrt{b ^{2}-4ac}/2a$$
you will get -b +- n/2a, so two different rational solutions

cwrw238 · Answer

like for example  (x - 2)^2 = 0  ?

anonymous · Answer

@cwrw238 yeah that's where I was going too :)

tennistar · Answer

So c is the answer

anonymous · Answer

but here says radicand in the cuadratic formula, not that the equation is perfect square

anonymous · Answer

Two different rational solutions
i insist on this

cwrw238 · Answer

oh radicand??

anonymous · Answer

radicand of the quadratic formula is a rather strange way to say "discriminant" aka $b^2-4ac$

cwrw238 · Answer

- not sure npw lol!!

anonymous · Answer

if it is a perfect square then there are two rational zeros

anonymous · Answer

@myko is right

anonymous · Answer

unless of course $b^2-4ac=0$ which is also a perfect square. in that case there is one rational zero

tennistar · Answer

ok thanks everyone

cwrw238 · Answer

yes - i misread the question -  but the radicand thing confused me