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OpenStudy (anonymous):
factor maybe?
start with \(a^4(1+a^2)\)
OpenStudy (anonymous):
1a^4+a^6?
OpenStudy (mathsolver):
@satellite73 is correct
OpenStudy (anonymous):
but i did that is it correct?
OpenStudy (mathsolver):
I'm afraid you have ended up where you stared.
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OpenStudy (anonymous):
yeah but when u multiply what @satellite73 did thats what u get
OpenStudy (anonymous):
a^4(1+a^2)
OpenStudy (anonymous):
is that what yoou do can you please explain
OpenStudy (mathsolver):
first you must understand that a^6=a*a*a*a*a*a and a^4=a*a*a*a so if you factorise these out you get (a*a*a*a)*(1+(a*a)) and that can be simplified to a^4(1+a^2)
OpenStudy (anonymous):
a^4+a^6
=(a^4)(1+a^2)
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OpenStudy (anonymous):
i made a mistake it was a^4+a^2
so you do that the same way like a*a*a*a+a*a*a
OpenStudy (anonymous):
2 would be hcm right
OpenStudy (anonymous):
a^4+a^2
=(a^2)(a^2 -1)
=a^2((a-1)(a+1))
=a=0 or a=1 or a=-1
OpenStudy (anonymous):
it could be either one of those?
OpenStudy (cwrw238):
no - thers no minus in this
a^2(a^2 + 1) are the factors - you can't factor any further
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