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Using complete sentences, explain how you would factor completely x^9 –27
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you can use the identity a^3 - b^3 = (a - b)(a^ - can't remember it - ill recheck
a^3 - b^3 = (a-b)(a^2 + ab + b^2) is what you're looking for cwrw238
thats it - thanx lol
you're welcome
so put a = x^3 and b = 3 into Jim's formula
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(x^3)^3 - 3^3 = (x^3 - 3)(x^3)^2 + 3x^3 + 3^2) = (x^3 - 3)(x^6 + 3x^3 + 9)
x^9 –27=0 ...firstly u take 27 to the right and u will get x^9 =27 then apply the 9th root both sides u will get x=\[\sqrt[9]{27}\] then x = (27)^(1/9) x=(3^3)^(1/9) x=3^(1/3) =\[\sqrt[3]{3}\] ........so ....u can use a calculator 2 find the answer if uwant 2 go further .....but it is not important
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