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how many positive divisors does 212100 have
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First, we have to factor 212100 can you do that yourself?
yes, got 2x2x3x5x5x7x101
Right, so to write it using exponents, we have\[212100=2^2\cdot3\cdot5^2\cdot7\cdot101\]To find the number of divisors, we have to pick certain subsets of these exponentsso that we don't repeat any numbers.
The number of choices we have for each exponent, is exactly \(e+1\) where \(e\) is a given exponent. Our exponents are \(\{2, 1, 2, 1, 1\}\) respectively. That means we have to multiply \[(2+1)\cdot(1+1)\cdot(2+1)\cdot(1+1)\cdot(1+1)=3\cdot2\cdot3\cdot2\cdot2=2^3\cdot3^2\]
Do the computations, you get that 212100 has exactly 72 positive divisors.
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