use the difference of squares to factor the expression 36x^8-9y^4
36
yeah, that's nonsense above
Hi Turing! I understand factoring to a point, but not this specific method, would you be willing to walk me through it? :)
wait, this should be in the math section right?
oh I actually thought I put it in the math section! Completely my bad!
lol I just followed the link, I didn't even know where we were :P
difference of squares is the formula\[a^2-b^2=(a-b)(a+b)\]so you need to identify: what is a and b in you problem compare and contrast: the form\[a^2-b^2=(a+b)(a-b)\]and yours\[36x^8-9y^4\]what are \(a\) and \(b\) in your particular case?
Sorry guys! I was talking in math chat and didn't pay attention to the actual page I was on!
honest mistake, no worries :)
a =36 and b= 9 ?
good effort, but notice a few things...
we need to keep the variables, so don't just drop x and y also not that I asked you what \(a\) and \(b\) are, but the formula starts with \(a^2\) and \(b^2\) so in your case, \(a^2=36x^8\) so what is \(b^2\) ?
also note*
b^2 = 9y^4 ?
yes :) so if a^2=36x^8 and b^2=9y^4 then what are a and b ?
I dont know :( would this be where I start factoring?
would I take the square root of 36x^8? im so bad at this. but im thinking haha.
yes, you just take the square root if\[a^2=36x^8\]then \[a=\sqrt{36x^8}\]
simplify...
6 sq root(x^8) sorry I dont know how to make the square root symbol
that's fine, but what is \[\sqrt{x^8}\] ??? you can simplify that
x^4?
6x^4 so then b = 3y^2?
you got it :) now just plug those values of a and b into the formula for difference of squares I wrote above
36x^8 - 9y^4 = (6x^4 -3y^2) (6x^4 +3y^2) ? :)
yep :) good job! think you got the idea ?
yes! thanks so much! im actually super excited that I get it now!
that's all I can hope for :)
welcome!
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