-6-y1=4(3-x1
re-write in slope-intercept form show your work.
y=-4(3-x)-6
How did you get that?
I think you equation is incorrect
i can't say \(-6-y_1=4(3-x_1\) makes much sense
agreed
maybe it is supposed to be \(y-6=4(x-3)\)
Thumbs up Exactly
or maybe \[y+6=4(x-3)\] what was the original problem?
Well the first part of this was Consider the line that passes through the point (3, -6) and has a slope of 4. Write the equation of this line using point-slope form.
Did you miss write it?
oooh ok
No. Someone gave me that as an answer.
yup you missed placed the variables
they where incorrect no offence
satellite73's equation is how it should look
you are using \(y-y_1=m(x-x_1)\) but you need to understand that \(x_1\) and \(y_1\) and \(m\) are numbers, and the variables are \(x\) and \(y\)
That's fine. Glad you guys caught it (:
so in your case, \(m=4,x_1=3,y_1=-6\) and you should write \[y-(-6)=4(x-3)\] or \[y+6=4(x-3)\]
now the steps are always the same. multiply out using the distributive law on the right \[y+6=4x-12\] then subtract 6 to get \[y=4x-18\]
Can you write all the steps down? Its easier for me to understand. please.
i did not skip a single step i can rewrite it if you like but it is all there
Yes that would be better please.
I meant all as one reply.
Yeah the slope intercept form should be simplified as so y+6=4(x-3) y+6=4x-12 subtract 6 from both sides y=4x-6 There is the answer
general form is \[y-y_1=m(x-x_1)\] make the substitution with the numbers and get \[y-(-6)=4(x-3)\] or \[y+6=4(x-3)\] so far so good?
Yeah. I understand now. Their is also a part two and three. With this.
that is a direct substitution in to the point - slope form with the numbers you are given. then a) multiply out on the right hand side of the equal sign using the distributive law \[y+6=4x-12\]
b) subtract 6 from both sides to get \(y\) by itself and get \[y=4x-18\]
Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work
Well I think Satellite73 has got the rest of this.
ok lets go slow
\[y-y_1=m(x-x_1)\] is the "point - slope" form because what you are using is the point \((x_1,y_1)\) and the slope \(m\)
you replace \(m\) by 4, \(x_1\) by 3, and \(y_1\) by \(-6\) and get \[y-(-6)=4(x-3)\] or \[y+6=4(x-3)\] now the line is in the "point - slope" form
then to put it in the "slope - intercept" form you rewrite it to look like \(y=mx+b\) in other words you solve for \(y\)
What was the first part for then?
the steps to do this never change. multiply out on the right using the distributive law and get \[y+6=4x-12\]
subtract 6 to get \[y=4x-18\] and now it is in slope - intercept form
I thought y=4x-6 was in point-slope form?
It is the formula he is showing you is how to get to the point slope form
no for two reasons one is it is wrong for this problem two because that is the "slope-intercept" form
I'm so lost.. theirs three parts to this hole thing. and you said for part one it was y=4x-6 and then you got to put it in point slope.
once again POINT SLOPE is \(y-y_1=m(x-x_1)\) SLOPE INTERCEPT is \(y=mx+b\)
actually i never said that, it is wrong
Can we start over? I'll re post the hole question.
i think whitedragon said that, and it is incorrect
haha yeah no I didn't
I re-posted it.
repost and i will reply slowly hmmm Yeah the slope intercept form should be simplified as so y+6=4(x-3) y+6=4x-12 subtract 6 from both sides y=4x-6 There is the answer
What are closing costs? A. various fees paid monthly along with rent B. various fees paid every year as part of taxes C. various fees paid when a home purchase is finalized
Umm pray your not suppose to ask a question to answer a question
Why?
That's just not how it works, if you need help you ask a question in the "ask a question box" this area is for people to answer the question someone has asked.
I have to because i don't even know anything.
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