Solve the inequality -3x + 4 x + 8 and show all of your work.
oops
?
missing something in the question
Oh yeah. One second.
Solve an inequality the same way you would solve a regular equation. With this ONE exception: If you multiply or divide both sides by a NEGATIVE number, then you should change the direction of the inequality sign.
\(<, >, \geq , \leq\)
easy peasy parchesie. =D
Solve the inequality -3x + 4<= x + 8 and show all of your work.
fortunately you never have to divide by a negative number
Give it a try on your own and ask me any questions that come up =)
What's the first step? lol
Group like terms. Get x by itself.
Don't be intimidated. It's nearly the same as solving a normal equation.
add 4 and 8?
\[-3x+4\leq x+8\] add \(3x\) to both sides and get \[4\leq 4x+8\]
Get them on the same side first.
Now do I divide 4x by 4?
subtract 4 from 8 on bothsides then take 1 away from the negative 3x to get -2 then divide 4 by negative two to get...\[x \le -2\]
can you write all that out?
When your write it in words it confuses me.
yeah \[-3x+4 \le x+8\\[x \le -2\] \[-3x \le x + 4\] \[-2x \le 4\
−3x+4 ≤ x+8 First of all, these steps are exactly the same as if we were solving the problem −3x+4 = x+8 The first step is to get like terms together. That means I want x on one side and everything else on the other. −3x+4 ≤ x+8 Add 3x to both sides. 4 ≤ 4x+8 Subtract 8 from both sides. -4 ≤ 4x divide both sides by 4.
That is explains it a lot better. thank you(:
I think you're letting yourself get scared, but solving this kind of problem is almost exactly the same as normal equations. There is one little difference, and I want to show it to you.
-1<=x is the answer?
Yes, that's right. If you ever multiply or divide both sides by a negative number, you have to switch which way the inequality points. I looks like this: -2x < 6 divide both sides by (-2), and remember to switch the inequality sign x > -3
Can you help me with another one?. please.
sure
Solve the compound inequality 6x + 7 > 1 and 6x + 7 < 25 and show all of your work.
Solve each of them separately. Please show me your attempt.
You can do this. Trust me.
Divide 6 from 7?
Not yet. Get like terms together first.
7 minus 1?
Start with the actual whole inequality, do something to both sides, and show me the result. You're just making guesses -_-
No I'm not You said to start with the separately.. I don't get this. I honestly.
Please help me.
It's alright. Let's try some simple equations. I'll do an example, and then I'll give you one to try. Example: 3x + 1 = 7 I start by getting like terms together. I have 1 on the left, and 7 on the right, so I need to move 1 over to the left. How do I do that? Subtract 1 from both sides. What is the result when I do that? 3x + 1 - 1 = 7-1 which gives 3x = 6 Now, I have like terms grouped, but x is not by itself yet. x is multiplied by 3, so how do I get rid of it? Divide both sides by 3, which gives me 3x/3 = 6/3 x = 2
Now you try this one. 5x - 6 = 9
I need help with the problem I have given.
Right, but you don't know how to solve basic equations, so the best way for me to help you is to teach you that.
Are you here to learn, or are you here to get answers?
Is this right? Part 1: 6x +7>1 6x>-6 x>-1 6x + 7 < 25 6x<18 x<3 -1<x<3
Yes =)
And that is exactly what I'm looking for. Change the inequality one step at a time until it is solved for x.
How would graph that on an number line?
CAN YOU People tell me whats exactly the question?
Would it be a open circle on 1 then colored to the right connected to a open circle on 3 colored to the left?
Good =) Except be careful. Not 1, but -1. Right?
Oh yeah. I meant that.
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