Solve using substitution:
5y − x = -2
-2x = 6 − 10y
A. No solution
B. Infinitely many solutions
C. (3, -1)
D. (-8, -2)
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OpenStudy (zzr0ck3r):
same thing as the last
do you not see how I did it?
OpenStudy (anonymous):
yes but still dont understand. sorry /:
OpenStudy (zzr0ck3r):
x = 2 + 5y
-2(2+5y) = 6 - 10y
-4 -10y = 6 - 10y
no solutions because -4 != 6
OpenStudy (anonymous):
was that wrong which i did???
OpenStudy (anonymous):
i dont know yet its a review packet i have to do @sradha
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OpenStudy (anonymous):
what?
OpenStudy (anonymous):
let y = 0 for the first one what does x = 2
use -4 = 6 − 10y
OpenStudy (anonymous):
now what does y =?
OpenStudy (anonymous):
10y = 10
OpenStudy (zzr0ck3r):
no, there are no solutions. And that is not substitution
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OpenStudy (anonymous):
ahhh oppsy
OpenStudy (anonymous):
well i tried
OpenStudy (zzr0ck3r):
I took the first equation and changed it around to be x = somehting( you could have made it y = something) then pluf that in for x (or y ) in the second equation. the algebra works out to be -4 = 6 thus there are no solutions
OpenStudy (anonymous):
theres no solution for it............
OpenStudy (zzr0ck3r):
you can always graph these and see where the intersect (these two dont)