Question

Electron beam is accelerated from rest through pd 5000 V and impinge normally onto the wall of building with an incident current 25\(\mu\)A. What force is exerted on wall?

Answer 1

final kinetic energy of electron= charge * pd = e*V= 5000e
final momentum=sqrt(2m * 5000e)
in time t , the total loss of momentum =m*v*I*t/e
force = rate of change of momentum=d/dt (m*v*I*t/e) = mvI/e
= sqrt(2m * 5000e) * I/e
use