Question

Friends!!!!!
Help me with this log-
sove for x :

Ix-10I log(base2) x-3 = 2(x-10)

Answer 1

\[\left| x-10 \right| \log_{2}(x-3) = 2(x-10)\]

Answer 2

your questions i must say at one sight can give a person heart attackkkkkk wait i am solving

Answer 3

are the two answers 7 and 13/4

Answer 4

13/4 and 10

Answer 5

Have you got 2 cases for solving mod??

Answer 6

yes

Answer 7

7 is not satisfying the equation

Answer 8

see i solve the question you tell me where i am wrong

Answer 9

ok

Answer 10

case 1:
when x>10,mod(x-10)=x-10

Answer 11

so x-10 cancels on both sides
we get,,,,
log(base 2)(x-3)=2
x-3=4
x=7

Answer 12

but x > 10
therefore, it is discarded.

Answer 13

ya i forgot

Answer 14

in second case,
when x<10,
we have mod(x-10)=-(x-10)
-(x-10)log(base 2)(x-3)=2(x-10)
-log(base 2)(x-3)=2
log(base 2)1-log(base 2)(x-3)=2
log(base 2)(1/x-3)=2
1/x-3=4
x-3=1/4
x=13/4

Answer 15

log(base 2)1-log(base 2)(x-3)=2
how???

Answer 16

ok

Answer 17

i understod

Answer 18

because log(base 2)1=0
as log 1=0

Answer 19

i am not able to find the error so that x=10

Answer 20

second case is fine right?

Answer 21

ya

Answer 22

ok thanks!!!
help me with one more question ia am posting.

Answer 23

ok