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Computer Science 20 Online
OpenStudy (anonymous):

how many bits are required for a four-input multiplexer?

OpenStudy (anonymous):

um i dint get the qn.....but if u have 4 inputs....then u l need two switches so smthing like 4+2?

OpenStudy (nick67):

you need two bits to select one of the four input channel: 00, 01, 10, 11

OpenStudy (anonymous):

thank all......

OpenStudy (nick67):

you are welcome

OpenStudy (anonymous):

r u a computer scientist??

OpenStudy (nick67):

hy msamido, is it a question for me ?

OpenStudy (anonymous):

yes..

OpenStudy (nick67):

no, I'm just an engineer in Electronics

OpenStudy (anonymous):

nick67 @nick67 ummm a 4 pin multiplexer must have 4 inputs/bits can you show me an equation or truth table for a 4 pin multiplexer that only needs 2 input bits? logically this makes no sense to me because using your logic you could just as well have 1 bit going in. I probably wrong though I gonna google it some more...maybe you can explain before I find the answer. --calmchess

OpenStudy (nick67):

hi @calmchessplayer , let me better explain my point of view; speaking of a multiplexer (MUX), we may have an analog MUX or a digital MUX. In both cases we have more inputs and one output. Within the multiplexer we have a multi-position switch ( S ) that can close the connection between one of the input channels and the only output. The command logic needs as many bits to select the input channel as the following relation says: \[n _{bit} = \log_{2} (inCh)\] |dw:1340341391322:dw|

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