Question

Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).

y = x + 7

y = −3x + 3

y = x + 3

y = −3x + 7

Answer 1

For a line to be parallel to y = -3x + 12, it must have the same slope. What is the slope of the line?

Answer 2

That's what I'm trying to figure out.

Answer 3

I'll give you a hint. The line y = -3x + 12 is written in the slope-intercept form of the equation y = mx + b, where m = slope and b = y-intercept. So in order for both lines to be parallel, they must have the same slope. What is that slope?

Answer 4

The line \[y=-3x+12\]has a slope of -3 and a y-intercept of 12. The y-intercept is where x=0. So the new line, in order to be perpendicular to this line must also have a slope of -3. So our new line is given by\[y=-3x+b\]However, we don't know the value of b. We do know that the line goes through the point (-1, 6) or x = -1 when y = 6.\[6=-3(-1)+b\]Rearrange and solve for b.

Answer 5

Y=-3x+3

Answer 6

Correct!

Answer 7

Omg , thaaanks !

Answer 8

You're welcome.

Answer 9

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