Question

how to simplify a square root?

Answer 1

the equation i am doing is \[2\sqrt{3}-4\]

Answer 2

Depends...

\[\sqrt{4}=\sqrt{2*2}=2\]
\[\sqrt{12}=\sqrt{2*2*3}=2\sqrt{3}\]
\[\sqrt{-1}=i\]
\[\sqrt{-8}=\sqrt{2*2*2*-1}=2i\sqrt{2}\]

Answer 3

my answer should look like this (__√__)/__

Answer 4

For this you're using the Pythagorean Theorem

a^2+b^2=c^2 where c = hypotenuse

Answer 5

yes, but i don't know how I find the answer I need.

Answer 6

\[2^2+x^2=(2\sqrt{3})^2\]

Answer 7

Oh! I forgot to square the 2√3!

Answer 8

solving for x here, and remember that squaring a square root cancels it out because:

\[\sqrt{x}=x^{1/2}\]

Answer 9

\[(x^{1/2})^2=x^{2/2}=x^1=x\]

Answer 10

Got it? :D

Answer 11

yeah, Thanks.