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Mathematics 8 Online
OpenStudy (anonymous):

how to simplify a square root?

OpenStudy (anonymous):

the equation i am doing is \[2\sqrt{3}-4\]

OpenStudy (anonymous):

|dw:1340300701868:dw|

OpenStudy (anonymous):

Depends... \[\sqrt{4}=\sqrt{2*2}=2\] \[\sqrt{12}=\sqrt{2*2*3}=2\sqrt{3}\] \[\sqrt{-1}=i\] \[\sqrt{-8}=\sqrt{2*2*2*-1}=2i\sqrt{2}\]

OpenStudy (anonymous):

my answer should look like this (__√__)/__

OpenStudy (anonymous):

For this you're using the Pythagorean Theorem a^2+b^2=c^2 where c = hypotenuse

OpenStudy (anonymous):

yes, but i don't know how I find the answer I need.

OpenStudy (anonymous):

\[2^2+x^2=(2\sqrt{3})^2\]

OpenStudy (anonymous):

Oh! I forgot to square the 2√3!

OpenStudy (anonymous):

solving for x here, and remember that squaring a square root cancels it out because: \[\sqrt{x}=x^{1/2}\]

OpenStudy (anonymous):

\[(x^{1/2})^2=x^{2/2}=x^1=x\]

OpenStudy (anonymous):

Got it? :D

OpenStudy (anonymous):

yeah, Thanks.

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