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Mathematics 7 Online
OpenStudy (anonymous):

The limit lim (5^(x)-1)/x x->0 represents the derivative of some function f(x) at some number a. Find f and a.

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0}5^{x-1} \div x?\]

OpenStudy (turingtest):

l'hospital's rule

OpenStudy (anonymous):

or\[\lim_{x \rightarrow 0}5^{x}-1 \div x\]?

OpenStudy (anonymous):

second one

OpenStudy (turingtest):

\[\lim_{x\to0}{5^x-1\over x}\]

OpenStudy (anonymous):

yup @TuringTest

OpenStudy (turingtest):

use l'Hospital if you are allowed to; take the derivative of the top and bottom, then take the limit again

OpenStudy (anonymous):

well im not allowed to use l'hoapital rule

OpenStudy (turingtest):

hm....

OpenStudy (anonymous):

|dw:1340305376609:dw| then u will get indeterminant of the form 0/0 you apply L'HOSPITALS RULE

OpenStudy (turingtest):

@msamido the asker just stated that we cannot use l'Hospital here, so we must find another way

OpenStudy (anonymous):

...but i was thinking that ....it is indeterminant of the form 0/0 ...

OpenStudy (turingtest):

yeah\[{5^0-1\over0}=\frac00\]and l'Hospital \(does\) work, but apparently it's not allowed :(

OpenStudy (zarkon):

are you allowed to use one of the definitions of \(e\) \[\lim_{x\to0}{e^x-1\over x}=1\]

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