Question

√8a^8=?

Answer 1

\[\sqrt{8a^8}\]?

Answer 2

when you have two of the same terms within your square root you can take out so split up your function inside the square rot

\[8a^8=2*2*2*a^4*a^4\]

Answer 3

take out anythng with 2 same terms and leave the rest in the square root. You have two 2's and two a^4 with a remaining 2

Answer 4

√8a^8 = 8a^ 2/8 = 8a^1/4 which is fourth root of 8a

Answer 5

@Aditi_Singh

that is wrong as if you are to change that into that form it'd be

\[8^{\frac{1}{2}}a^{\frac{2}{8}}\]

Answer 6

if it was your way it'd have to be

\[\sqrt{(8a)^8}\]

Answer 7

I still dont get you @Outkast3r09 :( :/

Answer 8

so right now we have sqrt(8*a^8) = (8*a^8)^(1/2) and now we are going to use the properties of exponents where (ab)^m =(a^m)*(b^m) so in this case we got

(8^1/2)*(a^8/2) = (8^1/2)*(a^4) now we know 8=4*2 so let us replace with that as well and simplify a little more to get

((4*2)^1/2)*(a^4) and now let us use that property again to get (4^1/2)(2^1/2)(a^4) = 2sqrt(2)*a^4 :)

Answer 9

@Aditi_Singh , What hamza did is how'd you'd have to do it , if you wanted to go about doing the problem like that

the answer is not 4th root of 8a

it's \[2a^4\sqrt{2}\]

Answer 10

Argh!! .. That was so stupid of me.. not to understand what he meant about the problem!!.. Humph!! x(

Answer 11

Btw, yes, i do understand what was the question .. and indeed you are right .. @Outkast3r09 .. :) :P