Question

The figure shows three right triangles. Triangles JKM, KLM, and JLK are similar.

Theorem: If two triangles are similar, the corresponding sides are in proportion.
Using the given theorem, which two statements help to prove that if segment JL is x, then x2 = 100?

Answer
Segment JL × segment JM = 64
Segment JL × segment LM = 48

Segment JL × segment JM = 36
Segment JL × segment LM = 64

Segment JL × segment JM = 48
Segment JL × segment LM = 36

Segment JL × segment JM = 64
Segment JL × segment LM = 36

Answer 1

Two things:
1. Picture needed :P
2. Let us know what you think first.

Answer 2

*smacks self*. ok one second

Answer 3

i honestly do not know

Answer 4

uhhhh....I'm not too sure either. I know it must be either the second or fourth though (64+36=100).

Give me a couple more minutes to see where I get.

Answer 5

oh ok1

Answer 6

gahh i gotta goo

Answer 7

I think I've decided on the second one. For the reason I just said above, and the fact that JM is shorter. Also, if we find what \(x^2\) actually is, we can write the relation \[x^2=x\cdot x=JL\cdot(JM+LM)=(JL\cdot JM)+(JL\cdot LM)\]

Answer 8

The second one is what i was leaning toward too!!

Answer 9

Great minds think alike!

Answer 10

:D now if only i new these last few on my homework:/

Answer 11

Think about them for a few minutes, it'll help you. The stuff I have for homework usually take at least an hour or two per problem >.<

Answer 12

yea..:/..gahhh i have to have this and a practice test done by 7 pm..

Answer 13

What's your time zone?

Answer 14

eastern

Answer 15

its 5 36

Answer 16

Good luck :/

Answer 17

thanks...68 problems..hmmm

Answer 18

fifnished this one;)

Answer 19

awesome.

Answer 20

only missed about 4. thanks man!

Answer 21

You're welcome. Glad to help.