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Mathematics 8 Online
OpenStudy (anonymous):

can someone help me with my problem

OpenStudy (anonymous):

x-2 3 ---- = x+3 4

OpenStudy (anonymous):

Is that supposed to be: \[\frac{x-2}{x+3} = \frac{3}{4}\]

OpenStudy (anonymous):

that is correct

OpenStudy (anonymous):

You would need to use cross multiplication to solve this.

OpenStudy (anonymous):

can you show me step by step please

OpenStudy (anonymous):

Here's an example of how it works: \[\frac{a}{b} = \frac{c}{d}\] Multiply both sides by b: \[\frac{a \times b}{b} = \frac{c \times b}{d}\] Cancel out b on the left since b/b=1 \[a = \frac{c \times b}{d}\] Multiply both sides by d: \[a \times d = \frac{c \times b \times d}{d}\] Cancel out d on the right since d/d=1 \[a \times d = c \times b\] That's cross multiplication. If you look at it, you're taking the numerator of one side and multiplying it by the denominator of the other side and making it equal to the numerator of the opposite side multiplied by the denominator of the other side.

OpenStudy (phi):

if you start with (x-2)/(x+3) = 3/4 what do you get when you multiply both sides by 4 ?

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