A diagonal of a prism is any segment determined by two vertices that do not lie in the same face.
1. For a(n) pentagonal prism, determine the number of vertices per base?
2. The number of diagonals per vertex?
3. And the total number of diagonals?

Question

A diagonal of a prism is any segment determined by two vertices that do not lie in the same face. 
1. For a(n) pentagonal prism, determine the number of vertices per base?
2. The number of diagonals per vertex?
3. And the total number of diagonals?

kinggeorge · Answer

It's a pentagonal prism. That means each base is a pentagon, and thus has 5 sides. What does this mean about the number of vertices in one base?

anonymous · Answer

have no clue

anonymous · Answer

what equation would I use to figure this out?

kinggeorge · Answer

Here's a pentagon.|dw:1340316202623:dw|How many corners does it have?

anonymous · Answer

5

kinggeorge · Answer

Right. So we have 5 vertices per base. Now we need to look at the diagonals that any one vertex will have.

kinggeorge · Answer

|dw:1340316357321:dw|There's the pentagonal prism. Can you draw me just one diagonal between any two points?

anonymous · Answer

|dw:1340316502653:dw|

kinggeorge · Answer

Not quite. Since we're defining a diagonal such that they don't lie in any plane. 

I'm sorry, but something came up and I need to leave now. To get you thinking about the third part, there are two diagonals that you can draw from any one vertex. Hopefully you'll be able to get part 3 from that.

anonymous · Answer

yes thank you for your help the last answer is 10