A balanced die is rolled twice. Are the events "the sum of the two rollsis 8" and "the first roll comes up 3" independent?
no they are not, but this will take some work
the probability that the sum is and 8 is \(\frac{5}{36}\) by counting the number of ways to get an 8 on two dice
the probability that the sum is an 8 given that the first die is a 3, here we also count. the sample space now has 6 element namely (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) of those 6, one has a total of 8 so the probability that you roll and 8 GIVEN that the first die is a 3 is \(\frac{1}{6}\)
now since \(\frac{5}{36}\neq \frac{1}{6}\) that means the events are DEPENDENT
i.e. not independent
events A, B are independent means \(P(A|B)=P(A)\) and since this is not the case here, they are dependent
Thanks a lot!!!!
yw
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