An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the objects maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t² + 64t + 80?
Round to the nearest foot.

Question

An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the objects maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t² + 64t + 80?  
Round to the nearest foot.

anonymous · Answer

max is at vertex. first coordinate of the vertex is $-\frac{b}{2a}$ in this case it is $-\frac{64}{2\times -16}=2$

anonymous · Answer

replace $t$ by 2 to get your answer

anonymous · Answer

144ft?