Mathematics
8 Online
OpenStudy (anonymous):
Solve for y: 2 over 3y + 2 = 8
y = 11
y = -11
y = -9
y = 9
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OpenStudy (anonymous):
y=9
OpenStudy (anonymous):
Wait are you saying 2/(3y) + 2 or 2/(3y+2)?
OpenStudy (anonymous):
\[\frac{2}{3y+2}=8\]
multiply both sides by \(3y+2\) to clear the fraction. use parentheses
then multiply out using the distributive law
OpenStudy (anonymous):
I did it as 2/(3y) +2
OpenStudy (anonymous):
2/3y+2=8
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OpenStudy (anonymous):
oh maybe i am wrong
OpenStudy (anonymous):
I'm sorry about that.
OpenStudy (anonymous):
Ok then my answer was right. Satellite would have been right otherwise
OpenStudy (anonymous):
Actually I'm still confused about what the initial question was. Either way, you have the right answer
OpenStudy (anonymous):
now i am confused
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OpenStudy (anonymous):
Here I will re write it.
OpenStudy (anonymous):
i bet it is \(\frac{2}{3}y+2=8\) am i right?
OpenStudy (anonymous):
] Solve for y: 2/3y + 2 = 8
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
Haha ok then
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OpenStudy (anonymous):
So what's the answer? I'm lost.
OpenStudy (anonymous):
\[\frac{2}{3}x+2=8\] first step, subtract 2
OpenStudy (anonymous):
you get
\[\frac{2}{3}x=6\]
OpenStudy (anonymous):
My answer of y=9 is right.
OpenStudy (anonymous):
Oh I see.
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OpenStudy (anonymous):
then multiply both sides by the reciprocal of \(\frac{2}{3}\) which is \(\frac{3}{2}\) that will give you \(1x\) on the left, or as we now know \(x\)
OpenStudy (anonymous):
\[\frac{3}{2}\times \frac{2}{3}x=6\times \frac{3}{2}\]
\[x=6\times \frac{3}{2}=3\times 3=9\] as elly said
OpenStudy (anonymous):
Thanks (: