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the specific heat of a certain type of metal is 0.128 J/gC. What is the final temperature if 305 J of heat is added to 58.3 g of this metal initially at 20.0 degree C
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q = mcΔT 305 = 58.3(0.128)(T - 20) T = 61 C
T-60.83 °C the above answer is right!!!
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