The sides of a square that are 3 ft long increasingat a rate of 2 ft/min .how fast is the area that square increasing at that instant

Question

zzr0ck3r · Answer

are you doing related rates in your class?

anonymous · Answer

This is the new function defined by the condition:
$$f(x) = (2x+3)^{2}$$
where x represents minutes elapsed.

Expanding the equation:
$$f(x) = 4x^{2}+12x+9$$

Then the derivative would be:
$$8x+12$$


Mm. I'm not sure. Not an expert in calculus.. :s

shubhamsrg · Answer

let side be x
now dx/dt = 2 (given)
area = A =x^2
so dA/dt = d(x^2)/dt = 2x .(dx/dt) = 2x.2

since its asking you at that instant when x=3,,make that substitution and you'll get your ans..

shubhamsrg · Answer

@veximeer sorry buddy,,i'dd you're wrong..hmm..

shubhamsrg · Answer

i meant i'd guess**

anonymous · Answer

Me not an expert in calculus :))

shubhamsrg · Answer

nevermind ^_^