Question

hey
I'm looking for a solution of the ordinary differential equation y'' -c*y'+10=0 with y(0)=a and y(T)=b. Can anyone help me out? Thanks!

Answer 1

dy/dx=p
hence
dp/(c*p+10)=dx
then u have:
ln(c*p+10)=c*x+A A is a constant
or
c*p+10=exp(c*x+A)
c*(dy/dx)+10=exp(c*x+A)
dy/dx=(exp(c*x+A)-10)/c*
the final solution is:
y=(1/c*^2)exp(c*x+A)-(10/c*)x+B B is a constant
now you can use boundery conditoins

Answer 2

y'' -c*y'+10=0 or y'' -c*y'+10y=0

Answer 3

the problem is as I stated it, y'' -c*y' +10 = 0 i.e. it's inhomogeneous I believe. But your answer helps a lot! I think I can take it from there.

Answer 4

ok