Question

A right triangular park, ABC, is surrounded on three sides by square shaped buildings X, Y, and Z, as shown below.



If the area of building X is 144 square meters and the area of building Z is 1225 square meters, what is the area of building Y?

1081 square meters

1058 square meters

1369 square meters

2209 square meters

Answer 1

If building X's area is 144, then side BC of the triangle is √144 = 12. Similarly side AB is √35. You know two side of the triangle so use the Pythagorean Theorem to find the 3rd. Then square it to get the area of Building Y

Answer 2

area of the of square=side ^2
so to find AB
take the squareroot of 1225 =35
and to find BC take the squareroot of 144 =12

now by using pythagorian theorem find AC
\[AC^2=AB^2+BC^2 =12^2+35^2 =144+1225=1369\]
so the area of Y = 1360 since area of square = side^2
so AC^2

Answer 3

okay got it thanks:)

Answer 4

Source:- http://www.acalculator.com/graphing-calculator-online/