Question

If tan x ̊=z/10 and cos x ̊=10/y ,what is the value of sin x°?

Answer 1

\[\angle_{\triangle} = 180^o = \angle_A + \angle_B + \angle_C\]

SOH-CAH-TOA

Sin-Opposite-Hypotenuse


\[\arcsin()=\sin^{-1}() \rightarrow \theta =sin^{-1}\frac{opposite}{hypotenuse}\]

Answer 2

Use the formulas/rules above to find your relative angles, then it's a matter of remembering the definition of the sine function. This is definition stuff they are quizzing you on.

Answer 3

You already know one of the angles yes? (being that it's a right triangle)

Answer 4

im still a little bit confuse

Answer 5

Do you know what SOH-CAH-TOA stands for?

Answer 6

yes

Answer 7

\[\sin\theta = \frac{opp}{hyp}=\frac{z}{y}\]
\[\cos\theta = \frac{adj}{hyp}=\frac{10}{y}\]
\[\tan\theta = \frac{opp}{adj}=\frac{z}{10}\]

Answer 8

Label stuff visually on your diagram you have. Label the sides 10, y, and z according to what they are from the formulas.

Answer 9

If you can visualize it you'll find it's actually an easier problem than it first looked to be.

Answer 10

That's not at all like the diagram you posted. The square corner means it's a 90 degree angle. What you drew is oddly flipped. No big deal, but take a look at your image again.

Answer 11

huh?