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Mathematics 12 Online
OpenStudy (anonymous):

Simplify.

OpenStudy (anonymous):

\[\sqrt{12} - 2/5 \sqrt{75}\]

jhonyy9 (jhonyy9):

there is squarroot of 75 ?

jhonyy9 (jhonyy9):

and this sqrt75 is in denominator or numerator ?

jhonyy9 (jhonyy9):

so because this 5 can being indice of root too

OpenStudy (anonymous):

no its just \[\sqrt{15}\] alone

jhonyy9 (jhonyy9):

sqrt12 = can you continue it because 12=3*4 so than sqrt12= and calcule sqrt75 the same too so sqrt75=sqrt(25*3)= ?

OpenStudy (anonymous):

\[2\sqrt{3} and 5\sqrt{3} \]?

jhonyy9 (jhonyy9):

yes correct so than using these terms can you please rewriting your exercise ?

jhonyy9 (jhonyy9):

so than will be 2sqrt3 - (2*5sqrt3)/5 = can you continue it ?

OpenStudy (anonymous):

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