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Simplify.
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\[\sqrt{12} - 2/5 \sqrt{75}\]
there is squarroot of 75 ?
and this sqrt75 is in denominator or numerator ?
so because this 5 can being indice of root too
no its just \[\sqrt{15}\] alone
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sqrt12 = can you continue it because 12=3*4 so than sqrt12= and calcule sqrt75 the same too so sqrt75=sqrt(25*3)= ?
\[2\sqrt{3} and 5\sqrt{3} \]?
yes correct so than using these terms can you please rewriting your exercise ?
so than will be 2sqrt3 - (2*5sqrt3)/5 = can you continue it ?
|dw:1340388279205:dw|
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