A museum exhibit, ABCD, has infrared beams around it for security, as shown below. If the length of the beams is made three times the original length on each side, which statement is correct about the maximum area available for an exhibit to be displayed?
@Hero
Says "Which statement is correct about the maximum area available for an exhibit to be displayed?" but I don't see any given statements.
It becomes nine times the original area. It becomes twenty-seven times the original area. It becomes three times the original area. It becomes eighty-one times the original area.
One of the best ways to determine this is by example. 1. Start with making up values for the figure. 2. Then create another figure with three times each value per side. 3. Then calculate the area of each. 4. Divide the larger area by the smaller area. The figure appears to be a trapezoid so you should be familiar with the area of trapezoid formula in order to help you answer the question.
Okay I'll do that. Thank you!
so if it were 2*3*4*6=144 if I triple that it'd be 6*9*12*27=17496 17496/144=121.5?
6 x 3 = 18, not 27
You would have had it if you multiplied 6*3 = 18. Try again, but replace 27 with 18
6*9*12*18=11664 11664/144=81?
:D
Thanks! (:
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