What could be the ordered pairs representing vertices B and C of quadrilateral ABCD so that Sandstone Park is similar to Rock Park? B(7, 1), C(8, 0) B(3, -1), C(4, -2) B(8, 1), C(8, 0) B(6, 2), C(7, 1)
A view of Anytown, USA is shown on the grid below with Rock Park represented by quadrilateral RSTU. Due to overcrowding, another park will be built similar to Rock Park. Vertices A and D are plotted on the grid to represent two corners of new Sandstone Park.
@jim_thompson5910 hello :D can you help me out please?
Notice how RU is the length of 2 diagonals (along a unit square). Do you see this?
yes
so how many diagonals is AD?
ie how long is AD in terms of diagonals
1
So AD is half of RU
Which means that if ABCD is similar to RSTU, then every side of ABCD is half as long as its corresponding side on RSTU
So that means that AB, which corresponds to RS, is half as long as RS. RS is 4 units long. So AB is half that at 2 units.
Do you see how I'm getting this?
yes Im starting to understand
So where does B go?
(7,1)?
good, what about C?
(8,0) :)
you nailed it
yay, a quick question? does a glide reflection exist on a hexagonal tessellation? Im getting contradiction sources
contradicting*
hmm well you can translate for sure and I believe you can also reflect, so I don't see why not...do you have a picture of it?
I know you can translate, rotate, and reflect. but I'm not sure about a glide reflection.
a glide reflection is simply a combo of a translation and a reflection
in either order
wiki says not. & another source says that is is combining aspects of both translation and reflection. & that image is a translation/reflection so that makes me assume yes.
yeah I'd go with yes as well, which page says "no"?
okay . hmmm I will try to find it. it pretty much said. " a glide reflection is not a translation nor reflection"
hmm weird, well it is a combination of both
yes I agree. lol
I'm guessing you're referring to this "In glide reflection, reflection and translation are used concurrently much like the following piece by Escher, Horseman. There is no reflectional symmetry, nor is there rotational symmetry"
Yeah
well I think in that horse pic, there isn't any reflectional symmetry because the horses themselves don't have reflectional symmetry
but hexagons do have reflectional symmetry
regular hexagons that is
so that would make me think that glide reflectional symmetry exists in a hexagon tesselation
ohhh okay. sounds good.
alright
thank you :)))
you're welcome
would you be so kind? again..:) http://openstudy.com/study#/updates/4fe4eab7e4b06e92b87361ee
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