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integral of 3/(x^2+9) from sqrt(3) to 3
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\[\int\limits_{\sqrt{3}}^{3} \frac{3}{x^2 + 9}\]
pull out the 3 on top and you'll see what you have
also you can switch the x^2+9 to 9+x^2
yup it's arctan
I'm just trying to find out how to get the answer of pi/12.
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\[3\int\limits_{\sqrt{3}}^{3} \frac{1} {x^2 +9} = \frac{1}{3} \arctan \frac{x}{3}\]
actually I think I know what I did, I replaced the 1 with sqrt{3} and 3 lol.
I was wondering why it made no sense :P
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