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Solve the differential equation dy/dx = 5-y?
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I know if it was x I would just integrate, but with this y do I just send it over to the other side?
that's a separable DE.... dy/dx = 5-y ---> \(\large \frac{dy}{5-y}=dx \) now just integrate both sides...
u = 5-y du = -1 so it could be -integral of u'/u = dx
but they want in terms of y soo.... hmm
I will give you some example: dy/dx=5y with initial condition y(0)=2? dy/dx = 5y INT (1/y) dy = INT 5 dx ln(y) = 5x + c y = e^(5x + c) = a*e^(5x) y(0) = 2, 2 = a*e^0 = a y = 2e^(5x)
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but if you multiply and divide the y term for (-1) in the numerator you have the derivative of the denominator so you can put as -Ln(5-y)=x+C you take exponentials at both sides...
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