Question

derivative of 4/(e^x +e^-x)

Answer 1

\[\frac{4}{e^x+e^{-x}|}\]

Answer 2

the quotient rule should be vu'-uv'/v^2

Answer 3

Start with\[4\frac{d}{dx}(\frac{1}{e^x})+4\frac{d}{dx}(\frac{1}{e^{-x}})\]
Use the quotient rule to solve these two derivatives

Answer 4

4e^(-x) would be -4e^(-x) and 4e^x would be the same.

Answer 5

sorry - don't know what i was thinking of then
- you can use the quotient rule as u said

Answer 6

the quotient rule would be (e^x+ e^-x) *0(or is it just null) - 4(e^x - e^-x) all over (e^x+e^-x)^2

Answer 7

-4(e^x-e^-x)
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(e^x + e^-x)^2

Answer 8

v*du = 0 yes
u dv = 4 * (e^x + (-e^(-x) = 4(e^x - e^(-x))
- thats the correct numerator i think

Answer 9

ah - its - 4(e^x - e(^-x)) - u r right

Answer 10

While the quotient rule is the most formal way of calculating the derivatives of inverse exponential functions, you can do it more quickly by remembering this:

\[\frac{d}{dx}(e^{ax})=ae^{ax}\]
For example:\[\frac{d}{dx}(e^{-17x})=-17e^{-17x}\]