Question

Please help:

x^2+13x

Answer 1

Are we looking for solutions?

Answer 2

yes

Answer 3

Start by removing the x from both terms:\[x(x+13)=0\]
Do you know how to proceed?

Answer 4

subtract 13 from both sides?

Answer 5

first you can't find the solution without a left side, did it ask for the roots/zeroes of the function?

Answer 6

right* side

Answer 7

if it's asking for roots or zeroes

first start with

\[x^2+13x=0\] because when it asks for zeroes it's asking for x intercepts we know that y = 0,

in otherwords y=f(x)=x^2+13x in this case where y = 0

Answer 8

it's asking me to write the resulting perfect square in trinomial form

Answer 9

I came up with x^2+13x + 169/4= (x + 13/2)^2

Answer 10

first take half of 13

Answer 11

6.5

Answer 12

then square it it

Answer 13

42.25

Answer 14

now since you added 42.25 to one side you have to add 42.25 on the other side

Answer 15

\[x^2+13x+42.25=42.25\]

Answer 16

your perfect squre is the left side

Answer 17

x^2 +13x is the final answer?

Answer 18

no your trinomial is

\[Ax^2+Bx+C=x^2+13x+42.25\]

Answer 19

I see it now

Answer 20

this question is really weird because trinomial form is

Ax^2+Bx+C however when you do complete the square you get Ax^2+Bx+C-(B/2)^2

Answer 21

im lost