Question

What is the magnitude if the acceleration experienced by an electron in an E of 750 N/C ? How does the direction of the acceleration depende in the direction of the field at this point?

Answer 1

F=m.a

Answer 2

F=E.Q

Answer 3

two formula?

Answer 4

a=E.Q/m

Answer 5

Q is the electron charge,and m is the mass of electron

Answer 6

(750N/C) (9.1x10^-31) divided by ???

Answer 7

direction?

Answer 8

am i right with the Q ?

Answer 9

no..
q=1.6*10^-19
m=9.1*10^-31

Answer 10

then the e is 750 N/C ?

Answer 11

yup

Answer 12

what if -1.6*10^-19 ? what is the difference between this negative and the positive 1.6*10^-19 ?

Answer 13

yeah...i forgot...both electron and proton have the same charge..
for electron...it's negative...and for proton it's positive.

Answer 14

so for electron..-1.6*10^-19

Answer 15

so i will use negative in this problem? because of electron?

Answer 16

acceleration has opposite direction of field

Answer 17

so you mean, even if it is electron, it has acceleration so it will be positive?

Answer 18

the positive field will attract the electron

Answer 19

oh okay that means, when it attracts the electron it will be positive ?

Answer 20

how did u get the mass= 9.1*10^-31 ?

Answer 21

use google

Answer 22

is it constant? i cant find it on google. :( its shows Kinetic Energy and Electric Field

Answer 23

https://www.google.com.br/search?aq=f&sugexp=chrome,mod=10&sourceid=chrome&ie=UTF-8&q=mass+of+electron

Answer 24

wow thank you so much. God bless you :)