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9 over h ^{-3} Simplify?
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\[9 \over h ^{-3} \] Simplify?
Remember: \[1/a^{-x} = a^x\] So can you go further or not??
ummm? Let me see.
I thought the expression was already simplified.
you can take h in numerator by using the formula I have written above...
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i mean it look like this expression is already simplified to me.
Ok that is really great..
so it is?
ugh O_o
What you think what will be the answer???
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To expand upon what @waterineyes is stating: \[\frac{9}{h^{-3}}\] can be expressed as \[9*\frac{1}{h^{-3}}\] \[\frac{1}{h^{-3}}\] is an expression of \[\frac{1}{a^{-x}}\] and \[\frac{1}{a^{-x}} = a^{x}\]
thsnk you!
What's the answer you ended up with?
9h^3
Yep!
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yay!! Thank you so much for taking the time to help me. ^_^
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