Solve (cubed root of x - 3) – 5 = 16 Answer x = 5 x = 19 x = 52 x = 67
@legoauto220
\[(\sqrt[3]{x}-3)-5=16.\]Is this ur question?
x-3 is under the cubed root
\[\sqrt[3]{x-3}-5=16\]
k:) \[\sqrt[3]{x-3}=16+5=21.\]\[\implies (x-3)=21^3.\]\[\implies x=21^3+3.\]
just calculate now:)
i know i did that but thats not one of the options above
\[\huge \sqrt[3]{x-3}-5=16\] \[\huge \sqrt[3]{x-3}=21\] \[\huge x-3=9261\] \[\huge x=9264\] Can't be what you meant...
I did the same options are wrong:)
i guess its just 3 times the square root i got the answer now 52
x^3 = x cubed x\(^{1/3}\) = \(\sqrt[3]{x}\) = cube root of x
The are NOT the same thing, at all :D
i know i wish i could show you how its displayed because it shows the cubed root
ya @cplatt688 that must be if u want answer:) but u gt 2 question's solution one with cuberoot & one with 3 x......
3 sqrt (x) = 3x^(1/2)
Or in clearer writing: \[3\sqrt{x} = 3x^{1/2}\]
Got to always remember to be extra, extra careful with exponents (or fractional exponents, which are better known as "roots")
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